8+2x^2=4

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Solution for 8+2x^2=4 equation: 



8+2x^2=4

We move all terms to the left:

8+2x^2-(4)=0

We add all the numbers together, and all the variables

2x^2+4=0

a = 2; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·2·4
Δ = -32
Delta is less than zero, so there is no solution for the equation

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